#### Answer

$True$

#### Work Step by Step

$\frac{2}{5}$+$\frac{3}{5}$ =$\frac{5}{5}=1$, and 1 is an element of the natural numbers, which means the first statement is true.
For the second statement, plug in 100.
$9\times(100)^{2}\times(100+11)-9\times(100+11)\times(100)^{2}=0$
$90000\times111-999\times10000=0$
$9990000-9990000=0$
$0=0$, the second statement is also true.
Since both of the statements are true, the answer is $True$.